Javascript Reflection
Solution 1:
The technical reason why those methods are hidden is twofold.
First, when you execute a method on the Test object, "this" will be the untyped object returned at the end of the anonymous function that contains the public methods per the Module Pattern.
Second, the methods testOne, testTwo, and testThree aren't attached to a specific object, and exist only in the context of the anonymous function. You could attach the methods to an internal object and then expose them through a public method, but it wouldn't be quite as clean as the original pattern and it won't help if you're getting this code from a third party.
The result would look something like this:
var Test = function() {
varprivate = {
testOne : function () {},
testTwo : function () {},
testThree : function () {}
};
functiongetMethods() {
for (i in this) {
alert(i); // shows getMethods, but not private methods
}
for (i in private) {
alert(i); // private methods
}
}
return { getMethods : getMethods }
}();
// will return ['getMethods', 'testOne', 'testTwo', 'testThree']
Test.getMethods();
edit:
Unfortunately, no. The set of local variables aren't accessible via a single, automatic keyword.
If you remove the "var" keyword they would be attached to the global context (usually the window object), but that's the only behavior that I know of that is similar to what you're describing. There would be a lot of other properties and methods on that object if you did that, though.
Solution 2:
From http://netjs.codeplex.com/SourceControl/changeset/view/91169#1773642
//Reflection
~function (extern) {
varReflection = this.Reflection = (function () { returnReflection; });
Reflection.prototype = Reflection;
Reflection.constructor = Reflection;
Reflection.getArguments = function (func) {
var symbols = func.toString(),
start, end, register;
start = symbols.indexOf('function');
if (start !== 0 && start !== 1) returnundefined;
start = symbols.indexOf('(', start);
end = symbols.indexOf(')', start);
var args = [];
symbols.substr(start + 1, end - start - 1).split(',').forEach(function (argument) {
args.push(argument);
});
return args;
};
extern.Reflection = extern.reflection = Reflection;
Function.prototype.getArguments = function () { returnReflection.getArguments(this); }
Function.prototype.getExpectedReturnType = function () { /*ToDo*/ }
} (this);
Solution 3:
Javascript doesn't really have the notion of private anything. Because of that, javascript doesn't have a reflection API as such. The technique you're using doesn't so much make them private as render them inaccessible; they're hidden, not private. I think you could manage something by putting those methods somewhere manually.
Solution 4:
Part of the issue with your test code is that Test is the object created by your return statement: "{ getMethods : getMethods }
" It has no testOne, testTwo, or testThree methods; instead, those are only available within the same namespace as the original getMethods function.
Solution 5:
With a little change to the way the function is defined you can achieve what you want. Wrap the actual implementation of the function in an object literal it would then look like this:
(function() {
var obj = {
// private methodstestOne: function () {},
testTwo : function () {},
testThree: function () {},
// public methods
getMethods : function () {
for (i inthis) {
alert(i); // shows getMethods, but not private methods
}
}
};
return { getMethods : function(){return obj.getMethods();} }
})();
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